> |
with(inttrans): |
| (needed for Maple to understand many
of the following commands) |
Example 3.05.1 [part: inverse of
Y
(
s
)
to find the complete solution
y
(
t)
of an initial value problem]
> |
F(s,w) := (s-5)/((s-2)*(s-3)); |
|
(1) |
> |
invlaplace(F(s,w), s, t); |
|
(2) |
Example 3.05.2 [part: inverse of
Y
(
s
) to find the
complete solution
y
(
t
)
of an initial value problem]
> |
F(s,w) := (5*s^2+11*s-10)/((s+4)*(s^2+4*s+13)); |
|
(3) |
> |
invlaplace(F(s,w), s, t); |
|
(4) |
Example 3.06.1 - a standard inverse
> |
F(s,w) := 1/(s*(s^2 + w^2)); |
|
(5) |
> |
invlaplace(F(s,w), s, t); |
|
(6) |
Example 3.06.2 - a standard inverse
> |
F(s,w) := 1/(s^2*(s^2 + w^2)); |
|
(7) |
> |
invlaplace(F(s,w), s, t); |
|
(8) |
Example 3.07.2 - Laplace transform involving the Heaviside unit step function
> |
f(t) := Heaviside(t-4)*(t-4)^3; |
|
(9) |
|
(10) |
Example 3.07.3 - inverse Laplace transform involving the Heaviside unit step
function
> |
F(s,w) := exp(-5*s)/(s^2 + 4); |
|
(11) |
> |
invlaplace(F(s,w), s, t); |
|
(12) |
Example 3.07.5 - inverse Laplace transform involving the Heaviside unit step
function
> |
F(s,w) := exp(-3*s)*(3*s+1)/(s^2*(s^2 + 4)); |
|
(13) |
> |
invlaplace(F(s,w), s, t); |
|
(14) |
[which is equivalent to (3/4 + (
t
-3)/4 - 3/4 cos2(
t
-3) - 1/8 sin2(
t
-3))
H
(
t
-3) ]
Example 3.10.2 - a standard Laplace transform
|
(15) |
|
(16) |
Example 3.11.2 - a standard inverse Laplace transform
> |
F(s,w) := 1/(s^2 + w^2)^2; |
|
(17) |
> |
invlaplace(F(s,w), s, t); |
|
(18) |