Find the determinant and the inverse of the matrix
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Find the determinant of the matrix
![R =
[ cos theta -sin theta 0 ]
[ sin theta cos theta 0 ]
[ 0 0 1 ]](a5w09/q2a.gif)
A row operation could be used to reduce this determinant
to triangular form, but a cofactor expansion along the
last row or column is much easier:
![[expansion along last row or column]](a5w09/q2b.gif)
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[All matrices representing pure rotations have a determinant of 1.]
Find the determinant of the matrix
![C =
[ 0 1 2 3 ]
[ 0 0 2 0 ]
[ 3 10 12 20 ]
[ 0 0 0 4 ]](a5w09/q3a.gif)
Use row operations to transform the determinant into
upper triangular form:
![[swap rows]](a5w09/q3b.gif)
![[swap rows]](a5w09/q3c.gif)
OR one may use a cofactor expansion, starting
with any of column 1 or row 2 or row 4.
Expanding along row 4:
![[expand along row 4]](a5w09/q3d.gif)
![]()
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Find the determinant of the matrix
![D =
[ 1 3 5 1 1 ]
[ 2 1 4 2 2 ]
[ 0 4 3 0 3 ]
[ -1 -6 2 -1 2 ]
[ 2 8 -1 2 1 ]](a5w09/q4a.gif)
Columns 1 and 4 of this determinant are identical.
Immediately we have
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[Textbook, page 114, exercises 3.1, question 8(b)]
Show that

Try to eliminate the " 2a " term from
element (1,1) by the row operation
However, this introduces an unwanted new term
" –4x ", which can be eliminated in
turn by the row operation
The two row operations together leave a multiple of
" p " alone in the (1,1) element.
![[adjusting top row]](a5w09/q5b.gif)
![[adjusting top row]](a5w09/q5c.gif)
![[adjusting middle row]](a5w09/q5d.gif)
![[adjusting bottom row]](a5w09/q5e.gif)
![[swapping rows to obtain the desired form]](a5w09/q5f.gif)
Therefore

![F =
[ 1 1 0 ]
[ 2 1 c ]
[ c 0 1 ]](a5w09/q6a.gif)
Find the value(s) of c for which the
matrix F is singular.
Use a cofactor expansion along row 3 (column 3 also works
well):

![]()
OR one may reduce the determinant to triangular
form:


F is singular if and only if
det F = 0 ; that is
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If det X = 2 and det Y = 3 ,
then calculate the value of
where possible.
Under what circumstances does
not exist?.
Provided the two matrices X and
Y are of the same dimensions as each other, all
of the products in
exist.
The fact that det Y is not zero guarantees
that Y -1 exists.
Using the results
![]()

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The product
does not exist if and
only if the square matrices X and
Y have different dimensions.
The general 3×3 skew-symmetric matrix is
(where a, b, c
are any real numbers).
Find det K.
The determinant may be calculated by a cofactor expansion
along any row or down any column.
Arbitrarily choosing row 1:
![]()
OR one may reduce the determinant to triangular
form:
![[row operations]](a5w09/q8c.gif)
![[row operations]](a5w09/q8d.gif)
There is a row of all zero entries. Therefore, for all
values of a, b, c ,
![]()
and all 3×3 skew-symmetric matrices are singular.
Note that the same is not true for 2×2
skew-symmetric matrices.